Returning a string literal?

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  • Can a local variable's memory be accessed outside its scope? 16 answers

I have a dynamically allocated array of pointers, each of which points to a line of text in a file. I need to extract the fourth column of the file (the values in the file are separated by commas), so that I can be able to sort the file by that column later on. I've been able to extract the fourth column text, however I am unable to return it to use in my main function, and when I return it, it's blank, what could be the problem?

getStart finds the comma right before the needed column

int getStart(char** addresses, int index) { int i = 0; int count = 0; for(i=0;i < strlen(addresses[index]); i++) { if(addresses[index][i] == ',') count += 1; if(count == 3) return i+1; } }

getStop finds the comma right before the end of the needed column

int getStop(char** addresses, int index) { int i = 0; int count = 0; for(i=0;i < strlen(addresses[index]); i++) { if(addresses[index][i] == ',') count += 1; if(count == 4) return i; } }

getSubject takes all the characters in between the start and stop, and puts them into an array (which is what I need to return to main)

char* getSubject(char** addresses, int index) { int i = 0; int start; int stop; char* final; char subject[10]; start = getStart(addresses, index); stop = getStop(addresses, index); for(start; start<stop; start++) { subject[i] = addresses[index][start]; i++; } final = subject; printf("%s %s\n", final, subject); return final; }

The way that I know the function work is that

printf("%s %s\n", final, subject);

prints the proper values, however when I call it in main as follows:

char* test; test = getSubject(addresses, 43); printf("%s\n", test);

test prints a blank value. Why is this?

--------------Solutions-------------

You make final point to the local array subject, and then return that pointer. That means you are in fact returning a pointer to the local subject array, an array that goes out of scope once the function returns, leaving you with a stray pointer and undefined behavior.



You need to allocate memory for the final string, and there are generally two ways of doing it:

  1. Use e.g. strdup in the function to allocate memory and return a pointer to that new memory.
  2. Pass in a pointer to a buffer of enough memory as an argument to the function, and copy the string to that buffer.

you are returning a pointer to a stack variable, you cant do that. The stack is cleared once you return. Make a copy

return strdup(final);

the call must free it when finished with it

Category:c# Time:2017-12-02 Views:2

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